Question

A car starts at rest and begins to speed up with an acceleration of 1.7 m/s². What distance (in meters) does this car cover in 5.0 seconds?
(-it's kinematics)
(and plz give me a formula for distance.)
Also, the answer is not 130, or speed x time.

Answer 1

Explanation:

GIVEN:

A CAR AT REST BEGINS TO SPEED UP WITH AN ACCELERATION OF 1.7 M/S^2.

TO FIND:

DISTANCE COVERED IN 5 SECONDS.

SOLUTION:

INITIAL VELOCITY =0 M/S

FINAL VELOCITY= V

ACCELERATION =1.7 M/S^2

TIME =5 SEC

NOW FINDING FINAL VELOCITY;

V=U+AT

=V=0+1.7×5

=V=8.5 M/S

NOW FINDING DISTANCE COVERED IN 5 SECOND:

FOR THIS WE CAN SECOND AND THIRD EQUATION OF MOTION BOTH AS PER OUR CHOICE;

S=UT+1/2AT^2

V^2=U^2+2AS

BUT WE SECOND EQUATION OF MOTION;

S=UT+1/2 AT^2

=S=0+1/2×1.7×25

=S=1/2×80/2=20 M.

HENCE DISTANCE COVERED IS 20 M.