A car starts from a full top and in 20seconds is traveling 10m/s. What is the acceleration
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11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
A car starts from rest and ...
PHYSICS
A car starts from rest and accelerates uniformly for 10 s to a velocity of 8 ms
−1
. It then runs at a constant velocity and is finally brought to rest in 64 m with constant retardation. The total distance covered by the car is 584 m. Find the value of acceleration, retardation, and total time is taken.
MEDIUM
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CALCULATOR
Enter the know values to find unknown
Acceleration
Distance
Final Velocity
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
(Refer to Image)
V=at
⇒8=a10
⇒a=0.8m/s
2
V
2
=U
2
+2as
⇒U=8
2
+2×a64
⇒a=
2×64
−64
=−0.5m/s
2
Distance travelled= Area of graph
⇒584=
2
1
×10×8+8×t
1
+
2
1
×16×8
⇒584=40+8t
1
+64
⇒8t
1
=480
⇒t
1
=60
Total time= 10+60+16=86s
solution
Answer:
Explanation:
A car stars from a full to in 20 second is travelling 10 m/s what is the acceleration