Question

A car starts from a point 'A' and moves in a circular path of radius 1 km after which it returns back to mathcal A^ prime . What is the average velocity​

Answer 1

Answer:

Centripetal acceleration a

c

=

r

v

2

=

5

25

=5m/s

2

the tangential acceleration is given as a

T

=5m/s

2

so the net acceleration will be

2

5

2

+5

2

at angle π/4 to the a

T

so angle between this net acceleration and velocity vector will be π−

4

π

=3π/4