Physics, asked by supriyasingh964833, 1 month ago

a car starts from from rest and moves with constant acceleration of 5m/s² for 8s and then moves with constant velocity. find the distance covered in 12s from when it was at rest . ​

Answers

Answered by s83004648
0

Answer:

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Explanation:

320 m

s

1

=ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m

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