a car starts from from rest and moves with constant acceleration of 5m/s² for 8s and then moves with constant velocity. find the distance covered in 12s from when it was at rest .
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Answer:
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Explanation:
320 m
s
1
=ut+(1/2)at
2
=0+
2
1
×5×8
2
=160 m.
The velocity attained in 8 seconds is given by
v=u+at
=0+5×8=40 m/s.
The distance traveled in the next 4 seconds is
s
2
=40×4=160 m.
So, the total distance traveled by the car is s
1
+s
2
=160+160=320 m
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