Question

A car starts from its rest and squires a velocity of 54km/hr in 2 sec the mass of car is 1000 kg what is the force acting on it

Answer 1

Giveη :

Initial velocity = zero (i.e., rest)

Final velocity = 54km/h = 15m/s

Time interval = 2s

Mass of car = 1000kg

To Fiηd :

Force acting on the car$.$

Concept :

As per Newton's second law of motion, Force is defined as the rate of change of linear momentum.

• F = dp/dt

Momentum is defined as the product of mass and velocity.

• F = m(v - u)/dt

Calculatioη :

⇒ F = m(v - u)/dt

⇒ F = 1000(15 - 0)/2

⇒ F = 15000/2

⇒ F = 7500N

Answer 2

Answer:

Explanation:

F=MA

F=MV/T

F=1000×15/2 ( v=54×5/18=15m/s)

F=7500 N