A car starts from Point A on the x-axis and moves with a velocity of 2 i^ m/s for some time, makes a sharp 60 o turn towards the left and then travels for double the time at the same speed, where it meets a biker who started from the origin six seconds after the car, and traveled with a uniform velocity of \left (7 i^ +2 3 j^ )m/s. Find the distance of point A from the origin
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Explanation:
The answer is x axis
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Answer:
Explanation:
if time car travels in î direction is t. Car travels for 3t.
biker travels for (3t-6) as given in question ( biker starts 6 seconds later)
(see image to understand the following)
bc= 4tcos60î. +. 4tsin60j
= 2tî + 2√3tj
oa = xî , ab= 2tî
oc=oa+ab+bc=(x+4t)î + 2√3tj (1)
oc vector can also be found by using bikers velocity?
oc=7(3t-6)î + 2√3(3t-6)j. (2)
equate (1) and (2)
2√3t=2√3(3t-6) => t=3. ( 2√3 cancels and then put all the ‘t’ terms in one side of equation)
Substitute in (2)
x+4t=7(3t-6)
x+12=63-42=21
=> x = 9m
∴ the car is at point A which is 9m away from point of origin .
∴distance of point A from origin = 9m.
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