A car starts from point P and travels at "40km/hr in a certain direction at 8.00am.Another car starts after two hours from point P in the same direction and travels at " 60km/hr.Find the time at which the two cars meet.
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car start from point p and travels at 40 km per hour in a certain direction at 8:00 a.m. another car starts after 2 hours from point p in the same direction and travels at 60 km per hour find the time at which the two cars me the two classmates as the 8:00 a.m. + 2 a.m. equals to 10:00 a.m. this is the meats of two cars time
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Answer:
Answer is at 2:00 pm
Step-by-step explanation:
Car A starts at 8 am and after two hours car A is 80 km ahead of car B.
Car B travels at 60kmph so it will travel at relative speed of 60-40=20kmph
The time required to catch up 80 km with 20kmph speed is
t = d / s
t = 80/20
t = 4 hours
so car B needs 4 hours to catch up with A. Hence it takes 10+4 = 14 or 2 pm
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