A car starts from point P, travels 40 km due south and reaches a, men takes a night
turn and travels another 30 krn in a straight line to reach point . The total time taken by
the car for this journey is 2 h 46 min and 40 s. Calculate the following:
a) Average speed of the car for this journey in mis.
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Explanation:
a. average velocity = total distance traveled / total time taken
total distance = 40 km + 30 km= 70 km
total time = 2 hr 46 min 40 s = 10000 s
Now we know that the average velocity of a body is ratio of total displacement traveled to total time taken. In the attachment you can see and it is given that the cat turns right after 40km and the travels 30km. According to the attachment then the displacement of car will be, by Pythagorean theorem :
h^2 = p^2 + b^2
h^2 = 40^2 + 30^2
h^2 = 1600 + 900
h^2 = 2500
h^2 = = 50
Therefore we get the displacement of car to be 50km = 50,000km
Now the average velocity of car will be :-
av = 50000m/ 10000 s
av= 5m/s
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