A car starts from rest accelerates in a straight line at a constant rate of 3ms-2 for 12 seconds. Calculate the distance travelled by the bus during this time interval
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Answers
Answered by
2
Answer:
hi army!!
The acceleration(a) of the bus is 3 m/s². The given time at which the bus has traveled is 8 seconds. In order to find the distance traveled we need to apply the formula s = ut+1/2at² (the second equation of motion). So the answer by solving the equation would be 96
Answered by
1
Answer:
216 m
Explanation:
We have,
=> Initial velocity (u) = 0 m/s
=> Acceleration (a) = 3 m/s²
=> Time taken (t) = 12 sec
To find,
=> Distance covered (S)
Solution,
S = ut + 1/2at²
[2nd equation of motion]
=> S = 0(12) + 1/2 × (3)(12)²
=> S = 0 + 1/2 × 3 × 144
=> S = 432/2
∴ S = 216 m
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