Question

A car starts from rest accelerates in a straight line at a constant rate of 3ms-2 for 12 seconds. Calculate the distance travelled by the bus during this time interval

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Answer 1

Answer:

hi army!!

The acceleration(a) of the bus is 3 m/s². The given time at which the bus has traveled is 8 seconds. In order to find the distance traveled we need to apply the formula s = ut+1/2at² (the second equation of motion). So the answer by solving the equation would be 96

Answer 2

Answer:

216 m

Explanation:

We have,

=> Initial velocity (u) = 0 m/s

=> Acceleration (a) = 3 m/s²

=> Time taken (t) = 12 sec

To find,

=> Distance covered (S)

Solution,

S = ut + 1/2at²

[2nd equation of motion]

=> S = 0(12) + 1/2 × (3)(12)²

=> S = 0 + 1/2 × 3 × 144

=> S = 432/2

∴ S = 216 m