Question

A car starts from rest acquires a velocity of 180 m/s² in 0.05m/s². Find the acceleration

Answer 1

Correct Question :

• A car starts from rest acquires a velocity of 180 m/s in 0.05 h. Find the acceleration.

AnsWer :

• We're given that, a car start from the rest i.e initial velocity (u) will be 0 m/s and aquires a velocity of 180 m/s i.e final velocity (v) is 180 m/s and time interval (t) is 0.05 h.
• We're asked to find the Acceleration (a) of the car.

We can solve this question by using two methods/formulas :

• Acceleration = (Final Velocity - Initial Velocity)/time interval
• By using first equation of motion :- v = u + at

So, you can use both methods to solve this question. Here, I will use the second method i.e by using first kinematical equation of motion :

↠ v = u + at

Here,

• v = final velocity
• u = initial velocity
• a = Acceleration
• t = time interval

Plug in the known values in above given formula:

↠ 180 = 0 + a(0.05 × 3600)

↠ 180 = a(180)

↠ a = 180/180

↠ a = 1 m/s²

∴ The Acceleration (a) of the car is 1 m/s².

Answer 2

Answer:

$\huge \tt \: 1m/s²$

Concept: Rate of Change of Velocity

Explanation:

$\bf \: Here, final \: velocity= 180m/s$

$\bf \: Initial \: velocity = 0 \: m/s$

$\bf \: Time \: taken = 0.05h \: or \: 180s$

Acceleration = Final velocity - initial velocity/time

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf = \frac{(180-0)}{180 \: m {s}^{ - 2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf= 1\frac{m}{s}^{ 2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \huge \tt \color{teal}(or)$

$\bf \: u = 0 \: m/s(body \: starts \: from \: rest)$

$\bf \: v = 180m/s$

$\bf \: t = 0.05h=180s$

$\bf \: Using \: first \: equation \: of \: motion,$

$\bf \: v=u+at$

$\bf \: a=v-u/t$

$\: \: \: \bf \: \: =\frac{180-0}{180}$

$\bf \: \: \: \: \: =1m/s²$