Question

A car starts from rest acquires a velocity of 54 km per hour in 2 minutes find the acceleration and distance travelled by it?

Answer 1

u=0
v=54×1000/2×60 =4500 m/sec
t=2 min=2×60 sec
a=v-u/t
=4500/2×60
=25m/s^2

Answer 2

Since the car starts from rest, the initial velocity of the car = 0 m/s
The final velocity of the car = 54 km/h = 15m/s
Time taken = 2 min = 120 s

Therefore
Acceleration = (Final velocity - Initial velocity)/time
                      = (15 - 0)/120
                      = 15/120
                      = 1/8 m/s²
                      = 0.125 m/s²

Speed = distance/time
15 m/s = distance/120
Distance of the car = 1800 m

The acceleration is 0.125 m/s² and the distance is 1800 m.


Hope this helps you.