Question

a car starts from rest .after 20 seconds its velocity becomes 20m/s . find the acceleration and distance covered in20 seconds

Answer 1

Answer:

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Answer 2

Answer:

$\bigstar{\bold{Acceleration=1\:m/s^{2}}}$

$\bigstar{\bold{Distance\:covered=200\:m}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 20 m/s
• Time taken (t) = 20 s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Acceleration
• Distance covered

$\Large{\underline{\underline{\bf{Solution:}}}}$

Acceleration:

➠ First we have to find the acceleration of the car.

➠ By the first equation of motion we know that,

    v = u + at

➠ Substitute the data,

    20 = 0 +  a × 20

    a = 20/20

    a = 1 m/s²

➠ Hence acceleration of the car is 1 m/s²

    $\boxed{\bold{Acceleration=1\:m/s^{2}}}$

Distance travelled:

➠ Now we have to find the distance travelled by the car

➠By the third equation of motion,

   v² - u² =  2as

➠ Substitute the data,

    20² - 0² =  2 × 1 × s

    400 = 2s

    s = 400/2

    s = 200 m

➠ Hence distance covered by the car is 200 m

    $\boxed{\bold{Distance\:covered=200\:m}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

➠ The three equations of motion are:

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as