Question

a car starts from rest an travel with anunifo acceleration. the car travels100 metre in 5 seconds. what will be its final velocity​

Answer 1

Solution :

Initial velocity = 0

car travelled 100 m in 5 sec

s= 100 m , t = 5 s

we know that,

s = ut + ½ at²

100 = (0)(5) + ½a(5)²

100 = (25/2)a

a = 100 x 2/25

a = 8 m/s²

uniform acceleration a = 8 m/s²

final velocity (v²) = u² + 2as

v² = (0)² + 2(8)(100)

v² = 0 + 1600

v = √1600

v = 40 m/s

=> 40 m/s is a final velocity

Answer 2

ᎯᏁᏕᏯᎬᏒ

Given:-

Initial velocity (u) = 0

Distance (s) = 100 m

Time taken (t) = 5 s

$\orange {..............................................}$

To find:-

Final velocity (v)

Acceleration (a)

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Solution:-

${\star}~~~\boxed{\rm{s = ut + \frac{1}{2} a {t}^{2}</p><p>} }$

${\implies}100 = 0 \times 5 + \frac{1}{2} \times a \times 5 \times 5$

${\implies}100 = \frac{1}{2} \times a \times 25$

${\implies}100 \times \frac{2}{25} = a$

${\therefore}~~\red{a = 8 \: m {s}^{ - 2} }$

$\orange {..............................................}$

${\star}~~~\boxed{\rm{a = \frac{v - u}{t}} }$

${\implies}8 = \frac{v - 0}{5}$

${\implies}\frac{v}{5} = 8$

${\implies}v = 8 \times 5$

${\therefore}~~\underline{\underline{\red{v = 40 \: m/s }}}$

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