Question

a car starts from rest and accelerate at 2m/s for 5s then travels at a steady speed for another 5s in same direction the distance it has covered for entire 10s is​

Answer 1

Explanation:

• u=0m/s
• a=2m/s²
• t=5s

Therefore

a=v-u/t

2=v/5

v=10m/s

For first five seconds distance=ut+1/2at²

1/2×2×25

=25m

For another five seconds distance=s×t

10×5=50m

Total distance=25+50=75m

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Answer 2

u=0 bcz car start from rest..

a=2m/s^2..

t=5+5=10s..

now use the second equation of motion...

s=ut+1/2at^2

by putting the values...

s=9(10)+1/2(2)(10)(10)

s=90+1(100)

s=90+100

s=190m

therefore the distance it has covered for entire 10s is 190m...

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