A car starts from rest and accelerate with 2 minute per second square for 10 seconds after maintaining the velocity for 10 seconds it comes to rest decelerating 1 minute per second square
Answers
Answered by
1
By using the equation of motion
S=ut+0.5at²
D1=0.5x2x10²
D1=100m
velocity after 10 seconds=at=2x10=20m/s
D2= 20x10 = 200m
D3
=v²-u²/2s
=.400/[2x-1]
=200m
total distance covered
=D1+D2+D3
=100+200+200
=500m
S=ut+0.5at²
D1=0.5x2x10²
D1=100m
velocity after 10 seconds=at=2x10=20m/s
D2= 20x10 = 200m
D3
=v²-u²/2s
=.400/[2x-1]
=200m
total distance covered
=D1+D2+D3
=100+200+200
=500m
Anonymous:
Genius.
Answered by
2
Hey mate!
Here's your answer!!
According to the first law of motion,
v = u + at
we get,
v = 0 + 2 × 10
v = 20 m/s
Now from the second law of motion,
v²- u² = 2as
Substituting values, we get
400 = 4s
So s (Displacement) = 100 m
✌ ✌ ✌
#BE BRAINLY
Here's your answer!!
According to the first law of motion,
v = u + at
we get,
v = 0 + 2 × 10
v = 20 m/s
Now from the second law of motion,
v²- u² = 2as
Substituting values, we get
400 = 4s
So s (Displacement) = 100 m
✌ ✌ ✌
#BE BRAINLY
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