Physics, asked by Gopala24may, 1 year ago

A car starts from rest and accelerate with 2 minute per second square for 10 seconds after maintaining the velocity for 10 seconds it comes to rest decelerating 1 minute per second square

Answers

Answered by Prashant24IITBHU
1
By using the equation of motion
S=ut+0.5at²
D1=0.5x2x10²
D1=100m

velocity after 10 seconds=at=2x10=20m/s
D2= 20x10 = 200m

D3
=v²-u²/2s
=.400/[2x-1]
=200m

total distance covered
=D1+D2+D3
=100+200+200
=500m

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Anonymous: No problemo.
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Answered by Anonymous
2
Hey mate!

Here's your answer!!

According to the first law of motion,
v = u + at
we get,

v = 0 + 2 × 10
v = 20 m/s

Now from the second law of motion,

v²- u² = 2as

Substituting values, we get

400 = 4s
So s (Displacement) = 100 m

hope \: it \: helps \: you...
✌ ✌ ✌
#BE BRAINLY

Anonymous: Great!
Anonymous: No problemo.
Anonymous: you really mean that?Be Brainly..?
Anonymous: Then thats good einstein.
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