Question

A car starts from rest and accelerates at 1 m/s sq for 4sec. It the moves at a constant Velocity for next 10sec then decelearates at 2 m/s sq and finally comes to rest .
Total distance travelled by car is?​

Answer 1

Explanation:

During first 4s the distance traveled, x

1

=ut+at

2

/2=0+

2

1×16

=8m

At the end of these 4s it will gain velocity v=at=1×4=4m/s

So the new distance in next 10sec with constant velocity v

is x

2

=v×10=40m

and then it comes to rest after travelling a distance s with retardation a

1

so this s= 2a

1

v2

=

2×2

16

=4m

Total distance is d=x

1

+x

2

+s=8+40+4=52m