Question

A car starts from rest and accelerates at 1 ms-2 for
4 s. It then moves at a constant velocity for
next 10 s, then decelerates at 2.0 ms-2 and finally
comes to rest. The total distance travelled by the car
is
(1) 52 m
(3) 48 m
(2) 40 m
(4) 46 m​

Answer 1

Answer:

$v = u + at \\ s = ut + \frac{1}{2}a {t}^{2}$