Question

a car starts from rest and accelerates at 3ms^-2 how long will it take to reach velocity of 30 m/s

Answer 1

Answer:

15 s

Step-by-step explanation:

As car starts from rest, initial velocity(u) = 0m/s

Acceleration (a) = 2m/s^2

Final velocity (v) = 30 m/s

We have to find time taken(t)=?

Formula: v = u + at

Solution: Substitute values in the formula.

v = u + at

30 = 0 + 2 × t

30 = 2t

t = 15 s

Answer 2

Given:-  

• Initial velocity(u) = 0m/s
• Acceleration (a) = 2m/s^2  
• Final velocity (v) = 30 m/s

To find:-  

• Time taken(t) =

Using formula:-

• $\boxed{\bf{Final\:velocity\:=\:Initial\:velocity\:+\:Accleration\:\times\:Time}}$
• $\boxed{\bf{v\:=\:u\:+\:at}}$

where,

• v is the final velocity
• u is the initial velocity
• a is accleration
• t is time

Solution:-  

$\qquad\sf{:\implies\:v\:=\:u\:+\:at}$

$\qquad\sf{:\implies\:30\:=\:0\:+\:2\:\times\:t}$

$\qquad\sf{:\implies\:30\:=\:2\:t}$

$\qquad\sf{:\implies\:t\:=\:\dfrac{30}{2}}$

$\qquad\sf{:\implies\:t\:=\:15\:s}$