A car starts from rest and accelerates at 5 m/s2. At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s
Answers
Given info : A car starts from rest and accelerates at 5 m/s² . at t = 4s , a ball is dropped out of a window by a person sitting in the car.
To find : the velocity and acceleration of the ball at t = 6s, is ..
solution : initial velocity of the car, u = 0 m/s
acceleration of the car, a = 5m/s²
velocity of the car at t = 4s, v = 0 + 5 × 4 = 20 m/s [ using v = u + at ]
at the moment, when person sitting in the car dropped a ball, velocity of the ball equals the that of the car.
so, initial velocity of the ball, u = 20 m/s horizontally
acceleration acting on the ball is acceleration due to gravity [ cause it is freely falling ]
so, a = - 10m/s² downwards
at time, t = 6s - 4s = 2s
now using formula,
= =
now the magnitude of the velocity , v =
therefore the velocity and acceleration of the ball are m/s and 10 m/s² respectively.
Answer:
Given: A car starts from rest and accelerates at 5 m/s². At t=4s, a ball is dropped out of a window.
To find: The velocity and acceleration of the ball at t=6s.
Solution:
To find the velocity of the car at t = 4s, we use the formula,
Here, v is the final velocity of the car, u is the initial velocity of the car, a is the aaceleration of the care and t is the time.
Let the velocity of the ball due to the car be equal to ,
The initial velocity here, is zero because the car starts from rest.
Let the velocity of the ball due to the acceleration due to gravity be equal to .
So,
Here, a is replaced by g, that is, the acceleration due to gravity (10ms⁻²) and 2s is the time interval between 4s and 6s.
Hence, velocity of the ball, v,
.
The acceleration of the ball, a,
Therefore, the velocity and acceleration od the ball at t = 6s is 20√2 ms⁻¹ and 10√2 ms⁻².
Explanation: