Question

A car starts from rest and accelerates constantly and reaches a velocity of 32 m/s.It takes 4 sec to cover the distance. Then find the acceleration and the distance travelled by the car.​

Answer 1

Question:-

A car starts from rest and accelerates constantly and reaches a velocity of 32 m/s.It takes 4 sec to cover the distance. Then find the acceleration and the distance travelled by the car.

Answer:-

• s = 64m

Solution:-

Given,

• Car starts from rest [ u = 0 ] and reached a velocity of 32m/s. It takes 4sec to cover distance.

We have to use the first equation of motion to find the acceleration:-

u = 0 ; v = 32m/s ; t = 4sec ; a = ?

➦ v = u + at

➦ 32 = 0 + 4t

➦ 32 = 4a

➦ a = 32/4

➦ $\boxed{ \: a \: = \: 8m/s²}$

Now,

We have to find the distance by using the third equation of motion:-

➦ s = ut + 1/2 at²

➦ s = 0 × 8 + 1/2 × 8 × 4 × 4

➦ s = 4 × 4 × 4

$\boxed{ \: s \: = \: 64m}$

∴ The distance covered by the car is 64m.

Answer 2

Explanation:

Question:-

A car starts from rest and accelerates constantly and reaches a velocity of 32 m/s.It takes 4 sec to cover the distance. Then find the acceleration and the distance travelled by the car.

Answer:-

s = 64m

Solution:-

Given,

Car starts from rest [ u = 0 ] and reached a velocity of 32m/s. It takes 4sec to cover distance.

We have to use the first equation of motion to find the acceleration:-

u = 0 ; v = 32m/s ; t = 4sec ; a = ?

➦ v = u + at

➦ 32 = 0 + 4t

➦ 32 = 4a

➦ a = 32/4

➦ \boxed{ \: a \: = \: 8m/s²}

a=8m/s²

Now,

We have to find the distance by using the third equation of motion:-

➦ s = ut + 1/2 at²

➦ s = 0 × 8 + 1/2 × 8 × 4 × 4

➦ s = 4 × 4 × 4

\boxed{ \: s \: = \: 64m}

s=64m

∴ The distance covered by the car is 64m.