A car starts from rest and accelerates for 8 secs at a rate of 2m/sec square .Find the distance covered , Also find it's avg velocity during this period.
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Answer:
Let v, t1,t2 be the maximum velocity attained, time for which car accelerated and the time for which car retarded respectively t1 = (v - u)/a = (v - 0)/2 ...
Explanation:
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Explanation:
t=8sec
a=2m/sec^2
d=?
av=?
ut+ at1/2at^2
0×8+1/2(2)(8)^2
0+64
=64
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