Physics, asked by dachu85, 10 months ago

A car starts from rest and accelerates for 8 secs at a rate of 2m/sec square .Find the distance covered .Also find the avg velocity during the period
Pls ans with proper steps
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Answers

Answered by dhaneswarram83288067
0

Explanation:

I hope you understand my answer in brief

Attachments:
Answered by prasoonjha18
1

Answer:

The Distance (Distance and Displacement are same in this case as in every 9th grade question, the body travels in a straight line) traversed by the car is 64m and the velocity of the car is 16m/s.

Explanation:

u=0m/s

t=8sec

a=2m/{s}^2

s=?

v=?

2<sup>nd</sup> Equation of Motion :

s=ut+\frac{1}{2}a{t}^2

s=(0*8)+(\frac{1}{2}*2*8*8)

s=2*8*4

s=64m

1<sup>st</sup> Equation of Motion :

v=u+at

v=0+(2*8)

v=16m/s

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