A car starts from rest and accelerates uniformly at 3.0 m/s^2 and covers a distance of 216m in certain time. what is the time taken by the car to travel this distance
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initial velocity=0
acceleration (a)=3ms^-2
distance (s)=226m
time (t)=?
formula:
s=(a*t*t)÷2
226=(3*t*t)÷2
226×2=(3*t*t)
452÷3=t^2
t^2=150.66
t=12.274635093014s
acceleration (a)=3ms^-2
distance (s)=226m
time (t)=?
formula:
s=(a*t*t)÷2
226=(3*t*t)÷2
226×2=(3*t*t)
452÷3=t^2
t^2=150.66
t=12.274635093014s
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