Question

A car starts from rest and accelerates uniformly at a rate of 2 metre per second square. The velocity of the car and distance covered at the end of 8 seconds is

Answer 1

$\frak{given}\begin{cases} \: \quad \sf initial \: velocity(v) = 0 \: m {s}^{ - 1} \\ \: \quad \sf time \: taken(t) = 8sec \\ \: \quad \sf acceleration(a) = 2 {ms}^{ - 2} \end{cases}$

initial velocity is supposed to be zero because the body has started from rest.

We are asked to calculate the velocity attained by the body after traveling a distance till the end of 8 seconds. i.e final velocity is required to be calculated.

$\large \quad \quad \dag\underbrace{ \frak{ \purple{ 1st \: kinematical \: equation : -} \: } }$

$\large \quad \qquad\quad \bigstar\underline{ \boxed{ \sf{ \pink{v = u + at}}}} \bigstar$

Substitute the given values in this equation:-

$\\ \quad \qquad: \implies \sf v = 0 + 2 \times 8$

$\\ \quad \qquad : \implies \boxed{\boxed{\sf \orange{ v = 16m {s}^{ - 1} }}} \bigstar$

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ADDITIONAL DETAILS:-

2nd Kinematical equation:-

$\leadsto\underline{\boxed{\sf S = ut+\dfrac{1}{2}at^2}}$

3rd Kinematical equation:-

$\leadsto\underline{\boxed{\sf v^2-u^2= 2as}}$

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