Question

A car starts from rest and accelerates uniformly at the rate of 3 m/s² . What is the distance travelled by the car in 12 seconds?

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Answer 1

Answer: 216 metre

Explanation:

Data given, u=0 m/s

a=3 m/s²

t=12 s

Using second equators of motion,

s= ut + 1/2at²

Substitution of values,

1/2 (3) (12)²

216 metres

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Answer 2

$\blue\bigstar$Answer:

$\boxed{s \:= \:216\: m\:}$

$\green\bigstar$ Given:

• A car starts from rest, so, initial velocity (u) = 0 m/s²
• Acceleration (a) = 3m/s²
• Time (t) = 12 seconds

$\red\bigstar$To find:

• Distance(s) covered in 12 seconds = ?

$\blue\bigstar$ Solution:

Here, we have:

u = 0 m/s²

a = 3 m/s²

t = 12 seconds

So,

s = ?

We don't have any information about final velocity, so we can use the II equation of motion.

The II equation of motion is :

$\boxed{s\: = \: ut \: + \: \dfrac{1}{2}at²\:}$

Now by substituting their values,

s = ut + $\dfrac{1}{2}at²$

$\implies$ s = (0)(12) + $\dfrac{1}{2}(3)(12)²$

$\implies$s = 0 + (3)(12)(6)

$\implies$ $\boxed{s \:= \:216\: m\:}$

$\therefore$ the distance covered,

$\boxed{s \:= \:216\: m\:}$

$\pink\bigstar$Extra - Information:

The three equations of motion are :

• v = u + at
• s = ut + $\dfrac{1}{2}at²$
• 2as = v² - u²

Here,

• u = Initial Velocity
• v = Final Velocity
• t = Total Time taken
• a = Acceleration
• s = Total Distance Covered