Question

A car starts from rest and accelerates uniformly at the rate of 1 metre per second square for 5 seconds .It then maintains a constant velocity for 30 seconds. Then brakes are applied and the car is uniformly retarded to rest in 10 seconds .Find the total distance travelled by it.

Answer 1

Answer:

The total distance is 187.5 m.

Explanation:

Given that,

Acceleration $a = 1 m/s^2$

Time t = 5 s

The velocity is

Using equation of motion,

$v = u+at$

$v = 0+1\times 5$

$v = 5\ m/s$

According to graph ,

The total distance traveled

Area of OACE = area of OAD+area of ABCD +area of CDE

$D = \dfrac{1}{2}\times5\times5+30\times5+\dfrac{1}{2}\times10\times5$

$D = 187.5\ m$

Hence, The total distance is 187.5 m.

Answer 2

Answer:

Explanation:

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