Question

A car starts from rest and accelerates uniformly by 5 ms. We
sec?. How much distance is covered in above time interval?
A bullet is fired with a velocity of 150mis. It penetrates a wood by 5 cm and
retardation of the bullet and the time interval in which the bullet stops​

Answer 1

Answer:

Hope it helps¯\_(ツ)_/¯

Explanation:

Here, initial velocity of bullet is u=367m/s and final velocity is v=0m/s.

Distance traveled by bullet is d=0.0621m

If a be the acceleration of bullet.

Using v

2

−u

2

=2ad

0

2

−(367)

2

=2a(0.0621)

⟹ a=−1.08×10

−6

m/s

2

(negative sign indicates deceleration of bullet means it slows down).