A car starts from rest and accelerates uniformly by 5 ms. We
sec?. How much distance is covered in above time interval?
A bullet is fired with a velocity of 150mis. It penetrates a wood by 5 cm and
retardation of the bullet and the time interval in which the bullet stops
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Answer:
Hope it helps¯\_(ツ)_/¯
Explanation:
Here, initial velocity of bullet is u=367m/s and final velocity is v=0m/s.
Distance traveled by bullet is d=0.0621m
If a be the acceleration of bullet.
Using v
2
−u
2
=2ad
0
2
−(367)
2
=2a(0.0621)
⟹ a=−1.08×10
−6
m/s
2
(negative sign indicates deceleration of bullet means it slows down).
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