Question

A car starts from rest and accelerates uniformly for 10 seconds to a velocity of 8 metre per second. It then runs at a constant velocity and is finally brought to rest in 64 metre with a constant retardation. The total distance covered by the car is 584 metre. find the value of acceleration, retardation and total time taken.

Answer 1

Step-by-step explanation:

V=at

⇒8=a10

⇒a=0.8m/s

2

V

2

=U

2

+2as

⇒U=8

2

+2×a64

⇒a=

2×64

−64

=−0.5m/s

2

Distance travelled= Area of graph

⇒584=

2

1

×10×8+8×t

1

+

2

1

×16×8

⇒584=40+8t

1

+64

⇒8t

1

=480

⇒t

1

=60

Total time= 10+60+16=86s