Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car.

Answer 1

Answer:

a = 8m/s^2

Explanation:

u = 0 (since, from rest)

t = 5.21 sec

s = 110m

$s = ut + \frac{1}{2} at {}^{2}$

Therefore,

$\\ 110 = \frac{1}{2} a(5.21) {}^{2} \\ a = \frac{110 \times 2 }{(5.21) {}^{2} } = \frac{220}{27.1441}$

$\: \: \: \: = \frac{220}{27.2} = 8.088$

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Sometimes, when you get complicated numbers for problems, it is better to round them.

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Hope it helps...!

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