a car starts from rest and accelerates uniformly over a time of 5.21 secs for a distance of 110 m determine the acceleration of car.
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Formula is s = ut+1/2 at^2 (u = 0 because at rest)
110 = 0 * 5.21 + 1/2 a(5.21)^2
110 = 0 + 0.5(13.57)a
a = 110/13.57
= 8.10
Hope this helps!
110 = 0 * 5.21 + 1/2 a(5.21)^2
110 = 0 + 0.5(13.57)a
a = 110/13.57
= 8.10
Hope this helps!
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Answered by
2
Given
d = 110 m t = 5.21 seconds u= 0 m/s
Formula s = ut+1/2 at^2
hope it's help u
d = 110 m t = 5.21 seconds u= 0 m/s
Find:
a = ??
Formula s = ut+1/2 at^2
110 = (0 )*(5.21 )+ 0.5*(a)*(5.21 )2
110 = (13.57 )*a
a = (110 )/(13.57 )
a = 8.10 m/ s²hope it's help u
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