Question

a car starts from rest and accelerates uniformly over a time of 5.21 secs for a distance of 110 m determine the acceleration of car.

Answer 1

Formula is s = ut+1/2 at^2        (u = 0 because at rest)
              
              110  = 0 * 5.21 + 1/2 a(5.21)^2

              110 = 0 + 0.5(13.57)a

              a = 110/13.57

                  = 8.10


Hope this helps!

              

Answer 2

Given
d = 110 m t = 5.21 seconds u= 0 m/s

Find:

a = ??

Formula    s = ut+1/2 at^2

110  = (0 )*(5.21 )+ 0.5*(a)*(5.21 )2

110  = (13.57 )*a

a = (110 )/(13.57 )

a = 8.10 m/ s²

hope it's help u