Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m determine the acceleration of the car

Answer 1

$\huge\underline{\underline{\bf \orange{Question}}}$

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m determine the acceleration of the car

$\huge\underline{\underline{\bf \orange{Solution}}}$

$\large\underline{\underline{\sf Given:}}$

• Time ( t ) = 5.21 sec
• Distance ( s ) = 110 m

$\large\underline{\underline{\sf To\:Find:}}$

• Acceleration ( a ) .

✪$\large{\boxed{\bf \blue{Velocity=\dfrac{Distance}{Time}} }}$

$\implies{\sf v = \dfrac{110}{5.21} }$

$\implies{\bf v = 21.11\:m/s}$

✪$\large{\boxed{\bf \blue{Acceleration (a)=\dfrac{dv}{dt}} }}$

$\implies{\sf a = \dfrac{21.11}{5.21} }$

$\implies{\bf \red{Acceleration (a)=4\:m/s^2}}$

$\huge\underline{\underline{\bf \orange{Answer}}}$

Acceleration of the car ${\bf \red{4\:m/s^2}}$

Answer 2

To Find:

Acceleration ( a )

$\large{\boxed{\blue{Velocity=\dfrac{Distance}{Time}}}}$

$\implies{\sf v = \dfrac{110}{5.21} }$

$\implies{\bf v = 21.11\:m/s}$

$\large{\boxed{\bf \blue{Acceleration (a)=\dfrac{dv}{dt}}}}$

$\implies{\sf a = \dfrac{21.11}{5.21} }$

Acceleration of the car ${\bf \red{4\:m/s^2}}$