A car starts from rest and accelerates uniformly over a time of 5.2 sec for a distance of 110 m Determine the acceleration of the car
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Answer:
a = 8.136 m/s²
Explanation:
t = 5.2 seconds
S = 110 m
(Initial velocity) u = 0 m/s
By the second law of motion = S = ut + 1/2at²
110 = 0(5.2) + 1/2 * a *(5.2)²
110 = 0 + 13.52 * a
110 = 13.52 * a
a = 110 / 13.52
a = 8.136 m/s²
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