Question

A car starts from rest and accelerates uniformly over a time of 5.2 sec for a distance of 110 m Determine the acceleration of the car
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Answer 1

Answer:

a = 8.136 m/s²

Explanation:

t = 5.2 seconds

S = 110 m

(Initial velocity) u = 0 m/s

By the second law of motion = S = ut + 1/2at²

110 = 0(5.2) + 1/2 * a *(5.2)²

110 = 0 + 13.52 * a

110 = 13.52 * a

a = 110 / 13.52

a = 8.136 m/s²