Physics, asked by DeepThinker, 8 months ago

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 Upton Chuck is riding Giant Drop at Great America.If Upton free falls for 2.6 seconds,what will be his final velocity and how far will he fall?​

Answers

Answered by anicevijay58
1

Explanation:

using second eq of motion s=ut+1/2at

using second eq of motion s=ut+1/2at 2

using second eq of motion s=ut+1/2at 2

using second eq of motion s=ut+1/2at 2 as u=0, a=

using second eq of motion s=ut+1/2at 2 as u=0, a= t

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s =

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110 =8.10m/s

using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110 =8.10m/s 2

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