A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 Upton Chuck is riding Giant Drop at Great America.If Upton free falls for 2.6 seconds,what will be his final velocity and how far will he fall?
Answers
Explanation:
using second eq of motion s=ut+1/2at
using second eq of motion s=ut+1/2at 2
using second eq of motion s=ut+1/2at 2
using second eq of motion s=ut+1/2at 2 as u=0, a=
using second eq of motion s=ut+1/2at 2 as u=0, a= t
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s =
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110 =8.10m/s
using second eq of motion s=ut+1/2at 2 as u=0, a= t 2 2s = 5.21 2 2∗110 =8.10m/s 2