Question

A car starts from rest and accelerates uniformly over a time of 5 seconds for a distance of 110m. Determine the acceleration of the car.

Answer 1

Answer:

8.8 m/s'2

Explanation:

T=5s

S=110m

U=0( as the body started from rest )

2nd equ. of motion

s=ut+1/2at'2

110=0×5+1/2a(5)'2

110=0+25/2a

110×2/25=a

a= 44/5

a = 8.8 m/s2

Answer 2

$\Large\underline{\bf \orange{Given :}}$

• Initial velocity = 0 m/s

• Time = 5 s

• Displacement = 110 m

$\Large\underline{\bf \orange{To \: Find :}}$

• Acceleration of the car

$\Large\underline{\bf \orange{Solution :}}$

$\large\implies\boxed{\tt s = ut + \frac{1}{2} {at}^{2} } \\ \\\tt \implies 110 = 0 \times 5 + \frac{1}{2} \times a \times {5}^{2} \\ \\\tt \implies 110 = \frac{1}{2} \times a \times 25 \\ \\\tt \implies a = \frac{110 \times 2}{25} \\ \\ \implies\underline{ \boxed{ \tt a = 8.8 \: {ms}^{ - 2}}}$