Question

A car starts from rest and accelerates uniformly over a time of 8 seconds for a distance of 110 m. Determine the acceleration of the car.​

Answer 1

Answer:

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

=

5.21

2

2∗110

=8.10m/s

2

Answer 2

Answer:

Let us consider the acceleration of the car be a

So putting the given quantities in the above formula we have

⇒ 110 = 0×(8)+ (1/2)×a×(8)²

⇒ 110 = (1/2)×a×8×8

⇒ a = (110×2)/(8×8)

⇒a = 3.437 m/s²