Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 meters. Determine the acceleration of the car. *

Answer 1

t=5.21sec
s=110m
u=0
a=??
we will use 2nd equation of motion.

$s = ut + \frac{1}{2}a {t}^{2}$
110=0×5.21+1/2×a×(5.21)^2
110=1/2a×27.1441
110×2/27.1441=a
8.1=a

therefore acceleration is 8.1m/s^2

Answer 2

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