Question

A car starts from rest and accelerates uniformly to a speed of 72 km/h. over a distance of 500 m. A further acceleration raises the speed to 90 km/h. in 10 seconds .The brakes are now applied to bring the car to rest under uniform retardation in 5 seconds. Find the distance travelled during braking.

Answer 1

Answer:

1.8m/s

Explanation:

initial speed= 72km/h=72*1000/3600=20m/s

final velocity = 90km/h=90*1000/3600=25m/s

time=10seconds

ACCELERATION={final velocity- initial velocity } / time

                          ={90-72}/10

                            =18/10

                               =1.8 m/s^ 2

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Answer 2

Answer:

your answer is 1.8m/s

Explanation:

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