Question

A car starts from rest and accelerates uniformly to a speed of 72km/h over 500m. if a further acceleration raises the speed of 90km/h in 10 seconds find this acceleration and the further distance moved​

Answer 1

Answer:

1.8m/s

Explanation:

initial speed= 72km/h=72*1000/3600=20m/s

final velocity = 90km/h=90*1000/3600=25m/s

time=10seconds

ACCELERATION={final velocity- initial velocity } / time

                         ={90-72}/10

                           =18/10

                              =1.8 m/s^ 2