Question

A car starts from rest and accelerates uniformly to a speed of 72km/h over 500m. if a further acceleration raises the speed of 90km/h in 10 seconds find this acceleration and the further distance move​

Answer 1

Acceleration = 0.5m/s²

Distance = 225 m

Explanation:

Given Information -

After understanding the question, we get to know that the given question has two parts -

Part - 1-

• Initial velocity (u) =0km/hr=0m/s
• Final velocity (v) =72km/hr=20m/s
• Distance (s) =500m.

Part-2-

• Initial velocity (u) =72km/hr=20m/s(reason-the motion was further continued with a different velocity, making the final velocity as the initial velocity in other part)
• Final Velocity (v) =90km/hr= 25m/s
• Time= 10 seconds

To Find-

• Acceleration(a) by the car in second case.
• Distance covered by the car in second case.

Solution -

$\implies$ Acceleration refers to the rate of change in velocities in a period of time.

Mathematically - ${a=\frac{v-u}{t}}$

• $= \frac{25 - 20}{10}$

• $= \frac{5}{10}$

• a=0.5m/s²

Acceleration is 0.5m/s² .

ㅤ

$\implies$ Distance refers to the total pathway travelled by an object.

Mathematically - ${2as = v² -u² }$

• 2(0.5×s)=25² -20²

• 1s=625-400

• s=225m.

The distance travelled is 225 m.

Answer 2

Answer:

hey baria, who's that friend pls say to that mod !! its a request ^_^ im so confused ,

Explanation: