A car starts from rest and acceleration uniformly over a time of 5.21 seconds for a distance of live 110 m determine the acceleration of the car
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Answer:
a=7.36m/s^2
Explanation:
s=ut+1/2at^2
110=0+1/2a(5.21)^2
as u=0
110=1/2a(27.14)
110=a(13.47)
a=7.36m/s^2
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