Question

A car starts from rest and acquire a velocity of 54 km per hour in 2 second find acceleration distance travel by a car asssume motion of car is uniform

Answer 1

Hi friend!!!!!


Given, u=0

v=54kmph =54×5/18 m/s =3×5= 15m/s

t=2s

Now, a=(v-u)/t

=(15-0)/2=7.5m/s²

s=ut+1/2 at²

=1/2(7.5)(2)²

=1/2(7.5)(4)

=15m


I hope this will help u ;)

Answer 2

Hey there !!!!

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Car starts from rest so initial velocity (u)=0 

It travels with velocity (v) =54kmph = 54*5/18 = 15m/s

 time taken = 2 seconds

  v=u+at


  15=0+a*2

  15=2a

  a=15/2=7.5m/s²

   s=ut+at²/2

   s=0*2+7.5(2)²/2

    s=7.5*2=15m

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Hope this helped you..............