Question

A car starts from rest and acquires a velocity of 54km/h in 2 min. find the
(i) acceleration
(ii) distance travelled by the car during this time.

assume motion of the car is uniform

Answer 1

$\bf \: Aloha !!$

• Given that :-

Intial velocity. ,u = 0 m/s

final velocity , v = 54 km /hr

= ( 54 × 5 ) /18 m/s

= 15 m/s

Time , t = 2 min = 2×60 s = 120 second

$\bf we \: know \: \\ \\ \boxed { \bf a = \frac{v - u}{t} }$
putting the value

$\boxed {a = \frac{15 - 0}{120} = 0.125 \: {ms}^{ - 2} }$

By 2nd equation of motion we know

$s = ut + \frac{1}{2} \times a {t}^{2} \\ \\ = 0.125 \times 60 ×120 \: \\ \\ \boxed{ \bf s= 900 \: m}$

Hope this helps you ☺

Answer 2

answer starts from first attachment.

hope it will help you