A car starts from rest and aquire 54cm/h in 2s find accelaration distance travelled by the car assume the car to be uniform
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Answer:
0.125m/s^2 and 900m
Explanation:
U (initial velocity)= 0. (as car starts from rest)
v (final velocity)= 54km/hr = 15m/sec
time = 2 mins = 120 sec
(1) acceleration = v-u/t
=> 15 - 0/120
=> 15/120
=> 0.125 m/s²
(2) using third equation of motion
=>2as = v²-u²
=>2(0.125×s) = (15)² - (0)²
=>0.25×s=225
=>s = 225/0.25= 900m
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