Question

A car starts from rest and aquire 54cm/h in 2s find accelaration distance travelled by the car assume the car to be uniform

Answer 1

Answer:

0.125m/s^2 and 900m

Explanation:

U (initial velocity)= 0. (as car starts from rest)

v (final velocity)= 54km/hr = 15m/sec

time = 2 mins = 120 sec

(1) acceleration = v-u/t

=> 15 - 0/120

=> 15/120

=> 0.125 m/s²

(2) using third equation of motion

=>2as = v²-u²

=>2(0.125×s) = (15)² - (0)²

=>0.25×s=225

=>s = 225/0.25= 900m