Question

A car starts from rest and attains a velocity of 10 m/s in 40 seconds. The driver applies brakes and slows down the car to 5 m/s in 10 seconds. Find the acceleration of the car in both the cases.

Answer 1

Answer:in first case acceleration is 0.25ms^-2

Second case acceleration is 0.5ms^-2

Explanation:let's go over with first case at first.

V=u+at

10=0+a×40

a=0.25ms^-2

Now,the second case....

V=u+at

5=10-a×10

a=0.5ms^-2