A car starts from rest and attains a velocity of 10 metre per second in 40
seconds .the driver applies brakes and slows down the car to 5 metre per
second in 10 seconds. Find the acceleration of the car in both the cases?
Answers
Answer:
the first case: initial speed=0 final velocity=10m time=40seconds
acceleration= v-u/t
= 10-0/40
=1/4
= 0.25m/s^2
the second case: initial velocity=10 final velocity=5 t=10seconds
acceleration= v-u/t
= 5-10/10
= -5/10
= -1/2
= -0.5m/s^2
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Answer :-
Case (i) :-
Given :-
- Initial Velocity (u) = 0 m/s
- Final Velocity (v) = 10 m/s
- Time taken (t) = 40 seconds
To Find :-
- Acceleration (a) = ?
Solution :-
By using first equation of motion we get :
- v = u + at
Substituting the given values in above equation, we get :
→ 10 = 0 + a(40)
→ 10 = 40a
→ a = 10 ÷ 40
→ a = 1 ÷ 4
→ a = 0.25 m/s²
Therefore, Acceleration of car in Case (i) is 0.25 m/s².
____________________...
Case (ii) :-
Given :-
- Initial Velocity (u) = 10 m/s
- Final Velocity (v) = 5 m/s
- Time taken (t) = 10 seconds
To Find :-
- Acceleration (a) = ?
Solution :-
By using first equation of motion we get :
- v = u + at
Substituting the given values in above equation, we get :
→ 5 = 10 + a(10)
→ 5 = 10 + 10a
→ 5 - 10 = 10a
→ - 5 = 10a
→ a = -5 ÷ 10
→ a = - 0.5 m/s²
Therefore, Acceleration of car in Case (ii) is - 0.5 m/s².