A car starts from rest and attains a velocity of 10 metre per second in 40 second the driver applies brakes and slows down the car to 5 M per second in 10 seconds find the acceleration of car in both the cases
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solution.
Case 1
initial velocity, u= 0m/s
final velocity, v= 10m/s
time taken , t= 40 s
so, Acceleration= v-u/t
= 10-0/40
= 1/4
= 0.25m/s^2
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CASE 2
initial velocity, u= 10m/s
final velocity, v= 5m/s
time taken, t= 10 second
Acceleration, a= 5 - 10/ 10
= -5/10
= -0.5m/s^2
________________
Hope it helps you☺✌✌
Case 1
initial velocity, u= 0m/s
final velocity, v= 10m/s
time taken , t= 40 s
so, Acceleration= v-u/t
= 10-0/40
= 1/4
= 0.25m/s^2
---------------------------
CASE 2
initial velocity, u= 10m/s
final velocity, v= 5m/s
time taken, t= 10 second
Acceleration, a= 5 - 10/ 10
= -5/10
= -0.5m/s^2
________________
Hope it helps you☺✌✌
sheenu10:
thanks
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