Question

A car starts from rest and attains a velocity of 10m/s in 40 seconds. The driver applies brake and slows down the car to 5m/s in 10 seconds. Find the retardation of the car in both the cases.

Answer 1

Answer:

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Answer 2

ɢıvεŋ

A car starts from rest and attains a velocity of 10m/s in 40 seconds. The driver applies brake and slows down the car to 5m/s in 10 seconds.

Tσ Fıŋɖ

Find the retardation of the car in both the cases

Sσɭutıσŋ

As we know that

$\sf Acceleration=\dfrac{final\:velocity-initial\:velocity}{time\:taken}$

$\Large\sf a=\dfrac{v- u}{t}$

In first case

A car starts from rest and attains a velocity of 10m/s in 40 seconds.

• v = 10m/s
• u = 0m/s
• t = 40sec

➦ a = (v - u)/t

➦ a = (10 - 0)/40

➦ a = 10/40

➦ a = 1/4

➦ a = 0.25m/s

In second case

The driver applies brake and slows down the car to 5m/s in 10 seconds

• v = 5m/s
• u = 10m/s
• t = 10

➦ a = (v - u)/t

➦ a = (5 - 10)/10

➦ a = -5/10

➦ a = -1/2

➦ a = - 0.5m/s