Question

A car starts from rest and attains a velocity of 10m/s. The driver applies
brakes and slow down the car to 5m/s in 10 sec. Find the acceleration
of the car in both the cases​

Answer 1

Answer:

In first case:

u = 0

v = 10 m/s

t = 40 s

a = v - u/t

= (10 - 0)/40

= 10/40

= 0.25 m/s²

In second case:

u = 10 m/s

v = 5 m/s

t = 10 s

a = (5 - 10)/10

= -5/10

= -0.5 m/s²

Answer 2

acceleration of a body can be defined as the rate of the change of the velocity of a body per unit time.

Explanation:

• Let us consider the first case. Here the initial velocity u is equal to zero. The final velocity v is equal to 10 metre per second. The time taken t ,is given 10 seconds for both the cases

1. In first case:

a= (v-u)t

u = 0m/sec

v = 10 m/sec

t = 10 s

a = (v - u)/t

= (10 - 0)/10

= 10/10

= 1 m/s²

• In second case,Here the initial velocity u is equal to 10m/sec. The final velocity v is equal to 5m/sec metre per second.

u = 10 m/sec

v = 5 m/sec

t = 10 sec

a = (5 - 10)/10 m/s²

= -5/10m/s²

= -0.5 m/s²

• the negative value of acceleration signifies that the deceleration of the body is taking place

To know more about equations of motion,

state three equation of motion. which of them describes (a) velocity .

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