Question

a car starts from rest and attains a velocity of 12m/s in 2 minutes calculate it's acceleration​

Answer 1

Given :-

Initial velocity of the car = 0 m/s

Final velocity of the car = 12 m/s

Time taken by the car = 2 min

To Find :-

The acceleration of the car.

Analysis :-

Here we are given with the time taken, final and initial velocity of the car.

In order to find the acceleration substitute the given values in the question using the first equation of motion and find the acceleration of the car accordingly.

Solution :-

We know that,

• u = Initial velocity
• t = Time
• v = Final velocity
• a = Acceleration

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Final velocity (v) = 12 m/s

Initial velocity (u) = 0 m/s

Time (t) = 2 min = 120 sec

Substituting their values,

⇒ 12 = 0 + a × 120

⇒ a = (v-u) / t

⇒ a = (12 - 0) / 120

⇒ a = 12/120

⇒ a = 0.1 m/s

Therefore, the acceleration of the car is 0.1 m/s.

Answer 2

$\Large\bf{\color{cyan}GiVeN,}$

• A car starts from rest.

⇒ Initial velocity (u) = 0 m/s

• It attains a velocity of 12 m/s in 2 minutes.

⇒ Final velocity (v) = 12 m/s

⇒ Time (t) = 2 min. = (2 × 60) s = 120 s

$\bf\orange{We\:know\:that,}$

$\red\bigstar\:\:\bf{\color{peru}v\:=\:u\:+\:a\:t}$

$:\implies\:\:\bf{12\:=\:0\:+\:a\times{120}}$

$:\implies\:\:\bf{120a\:=\:12}$

$:\implies\:\:\bf{a\:=\:\dfrac{12}{120}\:}$

$:\implies\:\:\bf{a\:=\:\dfrac{1}{10}\:}$

$:\implies\:\:\bf\blue{a\:=\:0.1\:m/s^2\:}$

$\Large\bold\therefore$ The acceleration of car is 0.1 m/s².