Question

A car starts from rest and attains a velocity of 20m/s in 5s. Calculate the distance during this time​

Answer 1

Answer:

The car traveled 50 m while accelerating from 0 to 20 m/s in 5 seconds.

The distance d is from

d = v(avg) • t

where v(avg) is the average velocity during the time, or

v(avg) = v(initial) + ∆v/2.

Here v(initial) is 0 and ∆v is 20 m/s, so

v(avg) = 20 m/s / 2 = 10 m/s.

d = 10 m/s • 5 s = 50 m.