A car starts from rest and attains a velocity of 20m/s in 5s. Calculate the distance during this time
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Answer:
The car traveled 50 m while accelerating from 0 to 20 m/s in 5 seconds.
The distance d is from
d = v(avg) • t
where v(avg) is the average velocity during the time, or
v(avg) = v(initial) + ∆v/2.
Here v(initial) is 0 and ∆v is 20 m/s, so
v(avg) = 20 m/s / 2 = 10 m/s.
d = 10 m/s • 5 s = 50 m.
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